Ans: (B)
Hint : Let the angle be \(\theta\). Then, \(\cos \left(90^{\circ}-\theta\right)=\frac{(3 \hat{i}+4 \hat{j}+5 \hat{k}) \cdot(2 \hat{i}-2 \hat{j}+\hat{k})}{|3 \hat{i}+4 \hat{j}+5 \hat{k}| \times|2 \hat{i}-2 \hat{j}+\hat{k}|} \Rightarrow \sin \theta=\frac{3}{\sqrt{50} \sqrt{9}}=\frac{\sqrt{2}}{10}\)