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Ferric ion forms a Prussian blue precipitate due to the formation of
(A) \(\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\)
(B) \(\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{4}\right]\)
(C) \(\mathrm{Fe}(\mathrm{CNS})_{3}\)
(D) \(\mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{\sqrt{3}}\right.\)

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Ans: (D)
 Formula of Prussian blue \(=\mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}\)
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