Question

A charged particle of mass \(m\) and charge \(q\) is released from rest in an electric field of constant magnitude E. The kinetic energy of the particle after time t is :-
(a) \(\left(\mathrm{E}^{2} \mathrm{q}^{2} \mathrm{t}^{2}\right) / 2 \mathrm{~m}\)
(b) \(\left(2 \mathrm{E}^{2} \mathrm{t}^{2}\right) / \mathrm{qm}\)
(c) \((\) Eqm \() / 2 \mathrm{t}\)
(d)(Eq \(\left.^{2} m\right) / 2 t^{2}\)

Answer 1

Correct option (a) \(\left(\mathrm{E}^{2} \mathrm{q}^{2} \mathrm{t}^{2}\right) / 2 \mathrm{~m}\)
Explanation:
$$
\begin{aligned}
&\text { Here, } u=0, a=\frac{F}{m}=\frac{q E}{m} \\
&v=u+a t=0+\frac{q E}{m} t \\
&K E=\frac{1}{2} m v^{2}=\frac{m q^{2} E^{2} t^{2}}{2 m^{2}}=\frac{E^{2} q^{2} t^{2}}{2 m}
\end{aligned}
$$

Answer 2

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Answer 3

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