Question

A 2 m long rod of radius 1 cm which is fixed from one end is given a twist of 0.8 radians. What will be the shear strain developed ?

(A) 0.002  (B) 0.004  (C) 0.008  (D) 0.016

Answer 1

Correct option: (B) \(0.004\)
Explanation:
Given : \(L=2 m\)
\(r=1 \mathrm{~cm}=10^{-2} \mathrm{~m}\)
twist \(=\theta=0.8 \mathrm{rad}\)
angle of shear \(=\phi\)
\(=(\mathrm{r} \theta / \mathrm{L})\)
\(=\left\{\left(10^{-2} \times 0.8\right) / 2\right\}\)
\(=0.4 \times 10^{-2}\)
i.e. shear strain \(=0.004 \mathrm{rad}\)

Answer 2

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Answer 3

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