Question

Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be

(a) Mv/2 (b) Zero (c) 2Mv (d) Mv

Answer 1

Correct Option (d) Mv
Explanation
$$
F=\frac{d}{m t}(M v)=v \frac{d M}{d t}+M \frac{d v}{d t}
$$
As \(v\) is constant
$$
F=v \frac{d M}{d t}, \text { But } \frac{d M}{d t}=M k g / s
$$
To keep the conveyor belt moving force needed = vM newton.

Answer 2

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Answer 3

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