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A line with positive direction cosines passes through the point \(P(2,-1,2)\) and makes equal angle with co-ordinate axes. The line meets the plane \(2 x+y+z=9\) at point \(Q\). The length of the line segment \(P Q\) equals.
(A) 1 unit
(B) \(\sqrt{2}\) unit
(C) \(\sqrt{3}\) unit
(D) 2 unit

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Ans: (C)
Hint : Let d.c. of line is \((\mathrm{k}, \mathrm{k}, \mathrm{k})\)
$$
\begin{aligned}
&\Rightarrow 3 \mathrm{k}^{2}=1 \Rightarrow \mathrm{k}=\frac{1}{\sqrt{3}} \\
&\Rightarrow \text { d.c. of line is }\left(\frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}\right)
\end{aligned}
$$
Equation of a line passing through point \(p\) is
$$
\begin{aligned}
&\frac{x-2}{\frac{1}{\sqrt{3}}}=\frac{y+1}{\frac{1}{\sqrt{3}}}=\frac{z-2}{\frac{1}{\sqrt{3}}}=k \\
&\Rightarrow x=k+2, y=k-1, z=k+2 \\
&\therefore 2(k+2)+(k-1)+(k+2)=9 \\
&4 k=4 \Rightarrow k=1 \\
&\therefore \text { Point } Q \text { is }(3,0,3) \\
&P Q=\sqrt{1^{2}+1^{2}+1^{2}}=\sqrt{3} \text { units. }
\end{aligned}
$$
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