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If from a point \(P(a, b, c)\), perpendiculars \(P A\) and \(P B\) are drawn to \(Y Z\) and \(Z X\) planes respectively, then the equation of the plane \(\mathrm{OAB}\) is
(A) \(b c x+c a y+a b z=0\)
(B) \(b c x+\) cay \(-a b z=0\)
(C) \(b c x-\) cay \(+a b z=0\)
(D) \(b c x-\) cay \(-a b z=0\)

Ans(B)

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