Question

If \(\mathrm{I}=\lim _{x \rightarrow 0} \sin \left(\frac{e^{x}-x-1-\frac{x^{2}}{2}}{x^{2}}\right)\), then limit
(A) does not exist
(B) exists and equals 1
(C) exists and equals 0
(D) exists and equals \(\frac{1}{2}\)

Answer 1

Ans: (C)
Hint \(: I=\lim _{x \rightarrow 0} \sin \left(\frac{e^{x}-x-1-\frac{x^{2}}{2}}{x^{2}}\right)=\lim _{x \rightarrow 0} \frac{e^{x}-x-1-\frac{x^{2}}{2}}{x^{2}}=\lim _{x \rightarrow 0} \frac{e^{x}-1-0-x}{2 x}=\lim _{x \rightarrow 0} \frac{e^{x}-1}{2}=0\)

Answer 2

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Answer 3

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