Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 185,000 in 450 mL of water at 37°C.

Question

Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 185,000 in 450 mL of water at 37°C.

Answer 1

It is given that:
Volume of water, $\mathrm{V}=450 \mathrm{~mL}=0.45 \mathrm{~L}$
Temperature, $\mathrm{T}=(37+273) \mathrm{K}=310 \mathrm{~K}$
Number of moles of the polymer, $n=\frac{1}{185000} \mathrm{~mol}$ We know that:
Osmotic pressure, $\pi=\frac{n}{V} \mathrm{R} T$
$$\begin{aligned} &=\frac{1}{185000} \mathrm{~mol} \times \frac{1}{0.45 \mathrm{~L}} \times 8.314 \times 10^{3} \mathrm{~Pa} \mathrm{~L} \mathrm{~K}^{-1} \mathrm{~mol}^{-1} \times 310 \mathrm{~K} \\ &=30.98 \mathrm{~Pa} \\ &=31 \mathrm{~Pa} \text { (approximately) } \end{aligned}$$

Answer 2

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