Clearly, the numbers between 10 and 250 which are multiple of 4 are \(12,16,20, \ldots, 248\).
This is an AP with first term a=12, common difference da4. Let there be \(n\) terms in this \(A P\), then
\(a_{n}=248\)
\(\Rightarrow \mathrm{a}+(\mathrm{n}-1) \mathrm{d}=248\)
\(\Rightarrow 12+(n-1) \times 4=248\)
\(\Rightarrow(n-1)=59\)
\(\Rightarrow \mathrm{n}=60\)
