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An ideal gas expands in volume from \(1 \times 10^{-3} \mathrm{~m}^{3}\) to \(1 \times 10^{-2} \mathrm{~m}^{3}\) at \(300 \mathrm{~K}\) against a constant pressure of \(1 \times 10^{5} \mathrm{Nm}^{-2}\). The work done is
(a) - 900J  (b) -900kJ  (c) 270kJ  (d) 900kJ.

3 Answers

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The correct answer is:
(a) :
$$
\begin{aligned}
W &=-P \Delta V \\
&=-1 \times 10^{5}\left(1 \times 10^{-2}-1 \times 10^{-3}\right) \\
&=-1 \times 10^{5} \times 9 \times 10^{-3}=-900 \mathrm{~J} .
\end{aligned}
$$
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