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|
x
3
x
+
2
2
x
−
1
2
x
−
1
4
x
3
x
+
1
7
x
−
2
17
x
+
6
12
x
−
1
|
=
0
is true for
0
votes
asked
Dec 10, 2021
in
Sets, relations and functions
by
kritika
(
90.1k
points)
edited
Dec 26, 2021
by
kritika
|
x
3
x
+
2
2
x
−
1
2
x
−
1
4
x
3
x
+
1
7
x
−
2
17
x
+
6
12
x
−
1
|
=
0
is true for
(A) only one value of
x
(B) only two values of
x
(C) only three values of
x
(D) infinitely many values of
x
Your answer
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3
Answers
0
votes
answered
Dec 26, 2021
by
kritika
(
90.1k
points)
Ans: (D)
Hint :
|
x
3
x
+
2
2
x
−
1
2
x
−
1
4
x
3
x
+
1
7
x
−
2
17
x
+
6
12
x
−
1
|
=
0
R
3
→
R
3
−
3
R
1
−
2
R
2
|
x
3
x
+
2
2
x
−
1
2
x
−
1
4
x
3
x
+
1
0
0
0
|
=
0
Infinite values of
x
is possible.
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votes
answered
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by
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answered
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by
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3
answers
If
a
n
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>
0
)
be the
n
th
term of a G.P. then
|
log
a
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log
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a
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is equal to
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28
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24
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x
6
2
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−
2
3
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Dec 10, 2021
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Sets, relations and functions
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90.1k
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votes
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If
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−
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0
2
1
−
3
3
4
1
|
=
A
, then
|
13
−
11
5
−
7
−
1
25
−
21
−
3
−
15
|
is
asked
Dec 13, 2021
in
Sets, relations and functions
by
kritika
(
90.1k
points)
0
votes
3
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If
S
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|
2
r
x
n
(
n
+
1
)
6
r
2
−
1
y
n
2
(
2
n
+
3
)
4
r
3
−
2
n
r
z
n
3
(
n
+
1
)
|
, then the value of
∑
n
r
=
1
S
r
is independent of
asked
Dec 13, 2021
in
Sets, relations and functions
by
kritika
(
90.1k
points)
0
votes
3
answers
If
a
r
=
(
cos
2
r
π
+
i
sin
2
r
π
)
1
/
9
, then the value of
|
a
1
a
2
a
3
a
4
a
5
a
6
a
7
a
8
a
9
|
is
asked
Dec 13, 2021
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