Processing math: 100%
0 votes
in Sets, relations and functions by (90.1k points)
edited by
|x3x+22x12x14x3x+17x217x+612x1|=0 is true for
(A) only one value of x
(B) only two values of x
(C) only three values of x
(D) infinitely many values of x

3 Answers

0 votes
by (90.1k points)
Ans: (D)
Hint : |x3x+22x12x14x3x+17x217x+612x1|=0
R3R33R12R2|x3x+22x12x14x3x+1000|=0
Infinite values of x is possible.
0 votes
by
cialis without prescription <a href="https://ordergnonline.com/">tadalafil medication</a> best ed pills at gnc
0 votes
by
cialis tadalafil 5mg <a href="https://ordergnonline.com/">cialis 10mg over the counter</a> best ed drug

Related questions

...