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\(\left|\begin{array}{ccc}x & 3 x+2 & 2 x-1 \\ 2 x-1 & 4 x & 3 x+1 \\ 7 x-2 & 17 x+6 & 12 x-1\end{array}\right|=0\) is true for
(A) only one value of \(x\)
(B) only two values of \(x\)
(C) only three values of \(x\)
(D) infinitely many values of \(x\)

3 Answers

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Ans: (D)
Hint : \(\left|\begin{array}{ccc}x & 3 x+2 & 2 x-1 \\ 2 x-1 & 4 x & 3 x+1 \\ 7 x-2 & 17 x+6 & 12 x-1\end{array}\right|=0\)
$$
\begin{aligned}
&\mathrm{R}_{3} \rightarrow \mathrm{R}_{3}-3 \mathrm{R}_{1}-2 \mathrm{R}_{2} \\
&\left|\begin{array}{ccc}
\mathrm{x} & 3 \mathrm{x}+2 & 2 \mathrm{x}-1 \\
2 \mathrm{x}-1 & 4 \mathrm{x} & 3 \mathrm{x}+1 \\
0 & 0 & 0
\end{array}\right|=0
\end{aligned}
$$
Infinite values of \(x\) is possible.
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