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The remainder when \(7^{7^{7^{-7}}}(22\) times 7\()\) is divided by 48 is
(A) 21
(B) 7
(C) 47
(D) 1

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Ans: (B)
Hint : \(7^{7^{7-^{7}}}=7^{2 m+1}=7(49)^{m}=7(1+48)^{m}=48 k+7\)
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