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The equation \(z \bar{z}+(2-3 i) z+(2+3 i) \bar{z}+4=0\) represents a circle of radius
(A) 2 unit
(B) 3 unit
(C) 4 unit
(D) 6 unit

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Ans : (B)
Hint : Centre and radius of \(z \bar{z}+\bar{a} z+a \bar{z}+b=0\) are \(-a\) and \(\sqrt{|a|^{2}-b} \quad \therefore\) radius \(=\sqrt{13-4}=3\)
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