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Hyper conjugation involves overlap of the following orbitals
(a) \(\sigma-\sigma\)
(b) \(\sigma-\pi\)
(c)p-p
(d) \(\pi-\pi\)

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Hyperconjugation involves delocalization of \(\sigma\) and \(\pi\) bonds orbitals. ie it undergoes \(\sigma-\pi\) conjugation. The kind of delocalization involving sigma electrons of single bond and \(\pi \cdot\) electrons of multiple bond is called hyperconjugation. Hence \(b\) is the correct answer.
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