Question

Let \(A=\left(\begin{array}{ccc}3-t & 1 & 0 \\ -1 & 3-t & 1 \\ 0 & -1 & 0\end{array}\right)\) and \(\operatorname{det} A=5\), then
(A) \(t=1\)
(B) \(t=2\)
(C) \(t=-1\)
(D) \(t=-2\)

Answer 1

Ans: (D)
Hint : \(|A|=\left|\begin{array}{ccc}3-t & 1 & 0 \\ -1 & 3-t & 1 \\ 0 & -1 & 0\end{array}\right|=3-t=5, t=-2\)

Answer 2

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Answer 3

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