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A body starts from rest, what is the ratio of the distance travelled by the during the 4th and 3rd second ?

(a) 7/5 (b) 5/7 (c) 7/3 (d) 3/7

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Correct option (a) \(7 / 5\)
Explanation:
Distance covered in \(\mathrm{n}^{\text {th }}\) second is given by
Here, \(u=0\)
$$
\begin{gathered}
\therefore \quad s_{4}=0+\frac{a}{2}(2 \times 4-1)=\frac{7 a}{2} \\
s_{3}=0+\frac{a}{2}(2 \times 3-1)=\frac{5 a}{2} \\
\therefore \frac{s_{4}}{s_{3}}=\frac{7}{5}
\end{gathered}
$$
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