Correct option (a) \(7 / 5\)
Explanation:
Distance covered in \(\mathrm{n}^{\text {th }}\) second is given by
Here, \(u=0\)
$$
\begin{gathered}
\therefore \quad s_{4}=0+\frac{a}{2}(2 \times 4-1)=\frac{7 a}{2} \\
s_{3}=0+\frac{a}{2}(2 \times 3-1)=\frac{5 a}{2} \\
\therefore \frac{s_{4}}{s_{3}}=\frac{7}{5}
\end{gathered}
$$