Correct option (b) \(19.2 \mathrm{~kW}\)
Explanation:
Here,
Distance between two cities \(=150 \mathrm{~km}\)
Resistance of the wire,
\(R=\left\langle 0.5 \Omega \mathrm{km}^{-1} \times(150 \mathrm{~km})=75 \Omega\right.\)
Voltage drop across the wire,
$$
V=\left\{3 \mathrm{~km}^{-1} 1(150 \mathrm{~km})=1200 \mathrm{~V}\right.
$$
Power loss in the wire is
$$
\begin{aligned}
P &=\frac{V^{2}}{R}=\frac{(1200 \mathrm{~V})^{2}}{75 \Omega} \\
&=19200 \mathrm{~W}=19.2 \mathrm{~kW}
\end{aligned}
$$
