Question

Seven capacitors each of capacitance $2, \ldots F$ are to be connected to obtain a capacitance of $10 / 11 \mu \mathrm{F}$. Which of the following combination is possible?
(a) 5 in parallel, 2 in series
(b) 4 in parallel, 3 in series
(c) 3 in parallel, 4 in series
(d) 2 in parallel, 5 in series

Answer 1

Correct option (a) 5 In parallel, 2 In serles
Explanation:
5 capacitors in parallel gives $5 \times 2 \mu \mathrm{F}=10 \mu \mathrm{F}$. The 2 capacitors in series give $1 \mu \mathrm{F}$.
When they arc connected in series, total capacitance will be $10 \times 1 / 10+1=10$ $/ 11 \mu \mathrm{F}$.

Answer 2

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Answer 3

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