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A stone thrown upwards with speed u attains maximum height h, another stone thrown upward from the same point with speed 2u attains maximum height H. What is the relation h & H.

(a) 2h = H (b) 3h = H  (c) 4h = H (d) 5h = H

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Answer is (c) \(4 \mathrm{~h}=\mathrm{H}\)
Use \(v^{2}-u^{2}=2 a x .\) Here \(0 \cdot u^{2}=2 g h_{.}\)and \(0 \cdot 4 u^{2}=2 g H .\).
hence \(h / \mathrm{H}=1 / 4 .\) that is \(4 \mathrm{~h}=\mathrm{H}\).

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