0 votes
in Sets, relations and functions by (90.1k points)
edited by
If the vectors \(\vec{\alpha}=\hat{i}+a \hat{j}+a^{2} \hat{k}, \vec{\beta}=\hat{i}+b \hat{j}+b^{2} \hat{k}\), and \(\vec{\gamma}=\hat{i}+c \hat{j}+c^{2} \hat{k}\) are three non-coplanar vectors and \(\left|\begin{array}{lll}a & a^{2} & 1+a^{3} \\ c & c^{2} & 1+b^{3}\end{array}\right|=0\),
then the value of abc is
\(\begin{array}{llll}\text { (A) } 1 & \text { (B) } 0 & \text { (C) }-1 & \text { (D) } 2\end{array}\)

3 Answers

0 votes
by (90.1k points)
Ans: (C)
Hint : \(\left|\begin{array}{lll}\mathrm{a} & \mathrm{a}^{2} & 1 \\ \mathrm{~b} & \mathrm{~b}^{2} & 1 \\ \mathrm{c} & \mathrm{c}^{2} & 1\end{array}\right|(1+\mathrm{abc})=0\) \(\mathrm{abc}=-1[\because \vec{\alpha}, \vec{\beta}, \vec{\gamma}\) are non-coplanar vector \(]\)
0 votes
by
buy tadalafil 40mg for sale <a href="https://ordergnonline.com/">order generic cialis 10mg</a> the blue pill ed
0 votes
by
order tadalafil 10mg without prescription <a href="https://ordergnonline.com/">buy tadalafil 5mg without prescription</a> male ed pills

Related questions

...