Question

Consider the curve $y=$ be $^{-x / a}$ where a and $b$ are non-zero real numbers. Then
(A) $\frac{x}{a}+\frac{y}{b}=1$ is tangent to the curve at $(0,0)$
(B) $\frac{x}{a}+\frac{y}{b}=1$ is tangent to the curve where the curve crosses the axis of $y$
(C) $\frac{x}{a}+\frac{Y}{b}=1$ is tangent to the curve at $(a, 0)$
(D) $\frac{x}{a}+\frac{y}{b}=1$ is tangent to the curve at $(2 a, 0)$

Answer 1

Ans : (B)
Hint : $y-b=-\frac{b}{a}(x) \Rightarrow \frac{x}{a}+\frac{y}{b}=1$

Answer 2

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Answer 3

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