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Find the torque about the origin when a force of \(3 \hat{j} N\) acts on a particle whose position vector is \(2 \hat{k} m\).
A \(6 \hat{i} \mathrm{Nm}\)
в \(6 \hat{j} N m\)
(C) \(-6 \hat{i} N m\)
D \(6 \hat{k} N m\)

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Solution:
$$
\begin{aligned}
&\text { Given: } \vec{F}=3 \hat{j} N, \\
&\vec{r}=2 \hat{k} \\
&\text { We know, } \vec{\tau}=\vec{r} \times \vec{F}=2 \hat{k} \times 3 \hat{j} \\
&=6(\hat{k} \times \hat{j})=6(-\hat{i}) \\
&\vec{\tau}=-6 \hat{i} N m
\end{aligned}
$$

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