Question

Light with an average flux of \(20 \Omega / \mathrm{cm}^{2}\) falls on a non-reflecting surface at normal incidence having surface area \(20 \mathrm{~cm}^{2}\). The energy received by the surface during time span of \(1 \mathrm{minute}\) is :
A \(10 \times 10^{3} \mathrm{~J}\)
в \(12 \times 10^{3} \mathrm{~J}\)
(c) \(24 \times 10^{3} \mathrm{~J}\)
D \(48 \times 10^{3} \mathrm{~J}\)

Answer 1

Solution:
Energy received = Intensity \(\times\) Area \(\times\) Time
\(I=\frac{E}{A}\)
\(E=I A t\)
\(=\frac{20}{10^{-4}} \times 20 \times 10^{-4} \times 60\)
\(=24 \times 10^{3} \mathrm{~J}\)

Answer 2

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Answer 3

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