Question

The mean free path for a gas, with molecular diameter \(d\) and number density \(n\) can be expressed as :
A \(\frac{1}{\sqrt{2} n \pi d}\)
(B) \(\frac{1}{\sqrt{2} n \pi d^{2}}\)
C \(\frac{1}{\sqrt{2} n^{2} \pi d^{2}}\)
D \(\frac{1}{\sqrt{2} n^{2} \pi^{2} d^{2}}\)

Answer 1

Solution:
Mean free path for a gas sample \(\lambda_{m}=\frac{1}{\sqrt{2} \pi d^{2} n}\)
where \(d\) is diameter of a gas molecule and \(n\) is molecular density

Answer 2

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Answer 3

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