The capacitance of a parallel plate capacitor with air as medium is \(6 \mu F\). With the introduction of a dielectric medium, the capacitance becomes \(30 \mu F\). The permittivity of the medium is : \(\left(\epsilon_{0}=8.85 \times 10^{-12} C^{2} N^{-1} m^{-2}\right)\)

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The capacitance of a parallel plate capacitor with air as medium is \(6 \mu F\). With the introduction of a dielectric medium, the capacitance becomes \(30 \mu F\). The permittivity of the medium is : \(\left(\epsilon_{0}=8.85 \times 10^{-12} C^{2} N^{-1} m^{-2}\right)\)

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kritika · Answer 1 · 2021-12-29T05:53:54+0000

Solution:
\(C=K C_{0}\)
\(K=\frac{C}{C_{0}}\)
\(=\frac{30}{6}=5\)
\(K=\frac{\varepsilon}{\varepsilon_{0}}\)
\(\varepsilon=K \varepsilon_{0}\)
\(=5 \times 8.85 \times 10^{-12}\)
\(=0.44 \times 10^{-10} \mathrm{C}^{2} N^{-1} \mathrm{~m}^{-2}\

The capacitance of a parallel plate capacitor with air as medium is \(6 \mu F\). With the introduction of a dielectric medium, the capacitance becomes \(30 \mu F\). The permittivity of the medium is : \(\left(\epsilon_{0}=8.85 \times 10^{-12} C^{2} N^{-1} m^{-2}\right)\)

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