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A short electric dipole has a dipole moment of \(16 \times 10^{-9} \mathrm{C} m\). The electric potential due to the dipole at a point at a distance of \(0.6 m\) from the centre of the dipole, situated on a line making an angle of \(60^{\circ}\) with the dipole axis is :
\(\left(\frac{1}{4 \pi \epsilon_{0}}=9 \times 10^{9} N m^{2} / C^{2}\right)\)
A \(50 \mathrm{~V}\)
B \(200 \mathrm{~V}\)
c \(400 \mathrm{~V}\)
D zero

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Solution:
The electric potential due to the dipole,
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