Solution:
$$
2 \mathrm{Cl}(g) \longrightarrow \mathrm{Cl}_{2}(g)
$$
As the process involves bond formation \(\Delta H=-v e\) and as the number of gaseous particles are decreasing in the reaction \(\Delta S\) is also \(-v e\) i.e., \(\Delta_{r} H<0\) and \(\Delta_{r} S<0\)