Ans(D)
In the figure \(\triangle \mathrm{ABC}\) is the respective triangle, \(\mathrm{O}\) is the circumcentre. \(\angle \mathrm{AOB}=2 \angle \mathrm{ACB}=2 \times 30^{\circ}=60^{\circ} \Rightarrow \angle \mathrm{OAB}=\) \(\angle \mathrm{OBA}=60^{\circ} \Rightarrow \triangle \mathrm{OAB}\) is equilateral \(\Rightarrow \mathrm{OA}=\mathrm{AB}=\mathrm{OB}=10 \mathrm{~cm}\).