. A capacitor of capacitance \({ }^{\prime} C^{\prime}\), is connected across an ac source of voltage \(V\), given by \(V=V_{0} \sin \omega t\) The displacement current between the plates of the capacitor, would then be given by:
(A) \(I_{d}=V_{0} \omega C \cos \omega t\)
B \(I_{d}=\frac{V_{0}}{\Delta C} \cos \omega t\)
c) \(I_{d}=\frac{V_{0}}{\omega} \sin \omega t\)
D \(I_{d}=V_{0} \omega C \sin \omega t\)