A straight line through the point \((3,-2)\) is inclined at an angle \(60^{\circ}\) to the line \(\sqrt{3} x+y=1\). If it intersects the \(x\)-axis, then its equation will be
(A) \(y+x \sqrt{3}+2+3 \sqrt{3}=0\)
(B) \(y-x \sqrt{3}+2+3 \sqrt{3}=0\)
(C) \(y-x \sqrt{3}-2-2 \sqrt{3}=0\)
(D) \(x-x \sqrt{3}+2-3 \sqrt{3}=0\)
Ans(B)
