The electron concentration in an \(n\)-type semiconductor is the same as hole concentration in a \(p\)-type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them.
A current in \(n\)-type = current in \(p\)-type
B current in \(\mathrm{p}\)-type > current in \(\mathrm{n}\)-type
(c) current in \(n\)-type > current in \(p\)-type
D No current will flow in p-type, current will only flow in n-type
