The electron concentration in an $n$-type semiconductor is the same as hole concentration in a $p$-type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them.

The electron concentration in an

$n$ -type semiconductor is the same as hole concentration in a

$p$ -type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them.
A current in

$n$ -type = current in

$p$ -type
B current in

$\mathrm{p}$ -type > current in

$\mathrm{n}$ -type
(c) current in

$n$ -type > current in

$p$ -type
D No current will flow in p-type, current will only flow in n-type

2 Answers

The electron concentration in an $n$ -type semiconductor is the same as hole concentration in a $p$ -type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them.