An electromagnetic wave of wavelength ' $\lambda$ ' is incident on a photosensitive surface of negligible work function. If ' $m$ ' mass is of photoelectron emitted from the surface has de-Broglie wavelength $\lambda_{d}$, then:

An electromagnetic wave of wavelength '

$\lambda$ ' is incident on a photosensitive surface of negligible work function. If '

$m$ ' mass is of photoelectron emitted from the surface has de-Broglie wavelength

$\lambda_{d}$ , then:
A

$\lambda=\left(\frac{2 m}{h c}\right) \lambda_{d}{ }^{2}$
B

$\lambda_{d}=\left(\frac{2 m c}{h}\right) \lambda^{2}$
(C)

$\lambda=\left(\frac{2 m c}{h}\right) \lambda_{d}{ }^{2}$
D

$\lambda=\left(\frac{2 h}{m c}\right) \lambda_{d}{ }^{2}$

2 Answers

An electromagnetic wave of wavelength ' $\lambda$ ' is incident on a photosensitive surface of negligible work function. If ' $m$ ' mass is of photoelectron emitted from the surface has de-Broglie wavelength $\lambda_{d}$ , then: