Question

Q. What is the dimensional formula for universal gravitational constant \(G\) ?
A \(M^{-1} L^{2} T^{-2}\)
B \(M^{0} L^{0} T^{0}\)
(c) \(M^{-1} L^{3} T^{-2}\)
D \(M^{-1} L^{3} T^{-1}\)

Answer 1

Solution:
$$
\begin{aligned}
&F=\frac{G M_{1} M_{2}}{R^{2}} \\
&\Rightarrow G=\frac{F R^{2}}{M_{1} M_{2}} \\
&\therefore[G]=\frac{\left[M L T^{-2}\right]\left[L^{2}\right]}{\left[M^{2}\right]}=\left[M^{-1} L^{3} T^{-2}\right]
\end{aligned}
$$

Answer 2

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Answer 3

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