Question

Q. The dimensions of angular velocity, is
(A) \(\left[M^{0} L^{0} T^{-1}\right]\)
B \(\left[M^{2} L^{0} T^{-1}\right]\)
c \(\left[M L T^{-2}\right]\)
D \(\left[M L^{2} T^{-2}\right]\)

Answer 1

Solution:
The angular velocity is given by
$$
\begin{aligned}
&\omega=\frac{2 \pi}{T} \\
&\therefore[\omega]=\left[T^{-1}\right]=\left[M^{\circ} L^{\circ} T^{-1}\right]
\end{aligned}
$$

Answer 2

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