Q. A solution of urea (mol mass $56 \mathrm{gmol}^{-1}$ ) boils at $100.18^{\circ} \mathrm{C}$ at the atmospheric pressure. If $K_{f}$ and $K_{b}$ for water are $1.86$ and $0.512 \mathrm{Kkg} \mathrm{mol}^{-1}$ the above solution will freeze at

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Q. A solution of urea (mol mass $56 \mathrm{gmol}^{-1}$ ) boils at $100.18^{\circ} \mathrm{C}$ at the atmospheric pressure. If $K_{f}$ and $K_{b}$ for water are $1.86$ and $0.512 \mathrm{Kkg} \mathrm{mol}^{-1}$ the above solution will freeze at

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kritika · Answer 1 · 2022-01-03T02:22:24+0000

Solution:
$$
\begin{aligned}
&\Delta T_{b}=100.18-100=0.18 \\
&\frac{\Delta T_{b}}{\Delta T_{f}}=\frac{K_{b} m}{K_{f} m}=\frac{K_{b}}{K_{f}} \\
&\frac{0.18}{\Delta T_{f}}=\frac{0.512}{1.86} \\
&\Delta T_{f}=\frac{0.18 \times 1.86}{0.512}=0.654 \\
&T_{f}=(0-0.654)^{\circ} \mathrm{C}=-0.654^{\circ} \mathrm{C}
\end{aligned}
$$

Q. A solution of urea (mol mass \(56 \mathrm{gmol}^{-1}\) ) boils at \(100.18^{\circ} \mathrm{C}\) at the atmospheric pressure. If \(K_{f}\) and \(K_{b}\) for water are \(1.86\) and \(0.512 \mathrm{Kkg} \mathrm{mol}^{-1}\) the above solution will freeze at

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