Question

Q. Which reaction is not feasible?
A \(2 \mathrm{KI}+\mathrm{Br}_{2} \longrightarrow 2 \mathrm{KBr}+\mathrm{I}_{2}\)
B) \(2 \mathrm{KBr}+\mathrm{I}_{2} \longrightarrow 2 \mathrm{KI}+\mathrm{Br}_{2}\)
c \(2 \mathrm{KBr}+\mathrm{Cl}_{2} \longrightarrow 2 \mathrm{KCl}+\mathrm{Br}_{2}\)
D \(2 \mathrm{H}_{2} \mathrm{O}^{+} 2 \mathrm{~F}_{2} \longrightarrow 4 \mathrm{HF}+\mathrm{O}_{2}\)

Answer 1

Solution:
\(2 \mathrm{KBr}+\mathrm{I}_{2} \longrightarrow 2 \mathrm{KI}+\mathrm{Br}_{2}\) reaction is not possible because \(\mathrm{Br}\)-ion is not oxidised in \(\mathrm{Br}_{2}\) with \(\mathrm{I}_{2}\) due to higher electrode (oxidation) potential of \(\mathrm{I}_{2}\) than bromine.

Answer 2

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