Ans : (A)
Hint : \(P(\bar{B})=\frac{7}{10} \Rightarrow P(B)=\frac{3}{10}\) \(P(A \cup B)=P(A)+P(B)-P(A \cap B) \Rightarrow P(A)=\frac{5}{9}\)
\(\therefore \mathrm{P}(\mathrm{A}) \times \mathrm{P}(\mathrm{B})=\frac{5}{9} \times \frac{3}{10}=\frac{1}{6}=\mathrm{P}(\mathrm{A} \cap \mathrm{B})\) \(\Rightarrow \mathrm{A}, \mathrm{B}\) are independent