Question

The radius of the first Bohr orbit of a hydrogen atom is \(0.53 \times 10^{-8} \mathrm{~cm}\). The velocity of the electron in the first Bohr orbit is
(A) \(2.188 \times 10^{8} \mathrm{~cm} \mathrm{~s}^{-1}\)
(B) \(4.376 \times 10^{8} \mathrm{~cm} \mathrm{~s}^{-1}\)
(C) \(1.094 \times 10^{8} \mathrm{~cm} \mathrm{~s}^{-1}\)
(D) \(2.188 \times 10^{9} \mathrm{~cm} \mathrm{~s}^{-1}\)

Answer 1

Ans: (A)
 \(r=0.53 \times 10^{-8} \mathrm{~cm}=0.53 \times 10^{-8} n^{2}\)
\(\therefore \mathrm{n}=1\)
\(V=2.18 \times 10^{8} \mathrm{~cm} / \mathrm{s}\)

Answer 2

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Answer 3

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