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The difference between orbital angular momentum of an electron in a 4 f orbital and another electron in a 4 s orbital is
(A) \(2 \sqrt{3}\)
(B) \(3 \sqrt{2}\)
(C) \(\sqrt{3}\)
(D) 2

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Ans: (A)
 Orbital angular momentum \(=\sqrt{\ell(\ell+1)} \frac{h}{2 \pi}\)

For 4 f orbital; \(\ell=3 \therefore\) Orbital angular momentum \(=\sqrt{3(3+1)} \frac{h}{2 \pi}=2 \sqrt{3} \frac{h}{2 \pi}\)
For \(4 \mathrm{~s}\) orbital; \(\ell=0 \therefore\) Orbital angular momentum \(=0\)
\(\therefore\) Difference \(=(2 \sqrt{3}) \frac{\mathrm{h}}{2 \pi}\)
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