Question

The total number of alkyl bromides (including stereoismers) formed in the reaction \(\mathrm{Me}_{3} \mathrm{C}-\mathrm{CH}=\mathrm{CH}_{2}+\mathrm{HBr} \rightarrow\) will be
(A) 1
(B) 2
(C) 3
(D) No bromide forms
Ans: (C)

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