Question

The points \((-a,-b),(a, b),(0,0)\) and \(\left(a^{2}, a b\right), a \neq 0, b \neq 0\) are always lie on this line.
Hence, collinear
(A) collinear
(B) vertices of a parallelogram
(C) vertices of a rectangle
(D) lie on a circle

Answer 1

Ans : (A) Hint : The straight line through (a, b) and (–a, –b) is bx = ay. Obviously, (0, 0) and (a2 , ab) always lie on this line