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The differential equation representing the family of curves \(y^{2}=2 d(x+\sqrt{d})\) where \(d\) is a parameter, is of
(A) order 2
(B) degree 2
(C) degree 3
(D) degree 4

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Ans: (C)
Hint : \(y^{2}=2 d x+2 d^{3 / 2}\)
\(2 y \frac{d y}{d x}=2 d\)
Degree \(=3\)
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