Question

Let \(y(x)\) be a solution of \(\left(1+x^{2}\right) \frac{d y}{d x}+2 x y-4 x^{2}=0\) and \(y(0)=-1\). Then \(y(1)\) is equal to
(A) \(\frac{1}{2}\)
(B) \(\frac{1}{3}\)
(C) \(\frac{1}{6}\)
(D) \(-1\)
Ans: (C)

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