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If the following three linear equations have a non-trivial solution, then
$$
\begin{aligned}
&x+4 a y+a z=0 \\
&x+3 b y+b z=0 \\
&x+2 c y+c z=0
\end{aligned}
$$
(A) \(a, b, c\) are in A.P.
(B) \(a, b, c\) are in G.P
(C) \(a, b, c\) are in H.P.
(D) \(a+b+c=0\)

3 Answers

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Ans: (C)
Hint : To have non-trivial solution, \(\left|\begin{array}{lll}1 & 4 a & a \\ 1 & 3 b & b \\ 1 & 2 c & c\end{array}\right|=0 \Rightarrow \frac{1}{c}+\frac{1}{a}=\frac{2}{b}\)
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