Question

The angular points of a triangle are \(A(-1,-7), B(5,1)\) and \(C(1,4)\). The equation of the bisector of the \(\angle A B C\) is
(A) \(x=7 y+2\)
(B) \(7 y=x+2\)
(C) \(y=7 x+2\)
(D) \(7 x=y+2\)

Answer 1

Ans: (B)
Hint: Equation of \(A B: 3 y-4 x+17=0\)
Equation of \(B C: 4 y+3 x-19=0\)
Equation of bisectors
$$
\begin{aligned} 4 y+3 x-19 &=\pm(3 y-4 x+17) \text { (using position of points A and C with respect to bisectors) } \\ 7 y &=x+2 \end{aligned}
$$

Answer 2

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Answer 3

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