If one of the diameters of the circle, given by the equation \(x^{2}+y^{2}+4 x+6 y-12=0\), is a chord of a circle \(S\), whose centre is \((2,-3)\), the radius of \(S\) is
(A) \(\sqrt{41}\) unit
(B) \(3 \sqrt{5}\) unit
(C) \(5 \sqrt{2}\) unit
(D) \(2 \sqrt{5}\) unit
Ans(A)
