Question

A uniform capillary tube of length / and inner radius \(r\) with its upper end sealed is submerged vertically into water. The outside pressure is \(\mathrm{p}_{0}\) and surface tension of water is \(\gamma\). When a length \(\mathrm{x}\) of the capillary is submerged into water, it is found that water levels inside and outside the capillary coincide. The value of \(x\) is
(A) \(\frac{I}{\left(1+\frac{p_{0} r}{4 \gamma}\right)}\)
(B) \(I\left(I-\frac{p_{0} r}{4 \gamma}\right)\)
(C) \(I\left(I-\frac{p_{0} r}{2 \gamma}\right)\)
(D) \(\frac{1}{\left(1+\frac{p_{0} r}{2 \gamma}\right)}\)

Answer 1

Ans(D)

For air inside capillary, \(p_{0}(\ell A)=p^{\prime}(\ell-x)\) A where \(p^{\prime}\) is pressure in capillary after being submerged
\(\therefore \mathrm{p}^{\prime}=\frac{\mathrm{p}_{0} \ell}{\ell-\mathrm{x}}\)
Now since level of water inside capillary coincides with outside, \(\therefore \mathrm{p}^{\prime}-\mathrm{p}_{0}=\frac{2 \gamma}{\mathrm{r}}\)
\(\therefore \frac{p_{0} \ell}{\ell-x}-p_{0}=\frac{2 \gamma}{r} \Rightarrow x=\frac{\ell}{\left(1+\frac{p_{0} r}{2 \gamma}\right)}\)

Answer 2

tadalafil usa <a href="https://ordergnonline.com/">levitra or cialis</a> ed pills that work

Answer 3

cialis sales <a href="https://ordergnonline.com/">brand name cialis</a> buy pills for erectile dysfunction