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Three capacitors of capacitance \(1.0,2.0\) and \(5.0 \mu \mathrm{F}\) are connected in series to a \(10 \mathrm{~V}\) source. The potential difference across the \(2.0 \mu \mathrm{F}\) capacitor is
(A) \(\frac{100}{17} \mathrm{~V}\)
(B) \(\frac{20}{17} \mathrm{~V}\)
(C) \(\frac{50}{17} \mathrm{~V}\)
(D) \(10 \mathrm{~V}\)

3 Answers

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Ans(C)

$$
C_{e q}=\frac{10}{17} \mu F, Q=\frac{100}{17} \mu C
$$
Potential difference across \(2 \mu \mathrm{F}\) capacitor \(=\frac{100 / 17 \mu \mathrm{C}}{2 \mu \mathrm{F}}=\frac{50}{17} \mathrm{~V}\)
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