A block of mass $1 \mathrm{~kg}$ starts from rest at $\mathrm{x}=0$ and moves along the $\mathrm{x}$-axis under the action of a force $\mathrm{F}=\mathrm{kt}$, where is time and $k=1 \mathrm{Ns}^{-1}$. The distance the block will travel in 6 seconds is

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A block of mass $1 \mathrm{~kg}$ starts from rest at $\mathrm{x}=0$ and moves along the $\mathrm{x}$-axis under the action of a force $\mathrm{F}=\mathrm{kt}$, where is time and $k=1 \mathrm{Ns}^{-1}$. The distance the block will travel in 6 seconds is

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kritika · Answer 1 · 2021-12-14T08:52:28+0000

Ans: (A)
$$
\begin{aligned}
&F=k t=1 \times a=\frac{d v}{d t} \\
&v=\frac{k t^{2}}{2}=\frac{d x}{d t} \\
&x=\frac{k t^{3}}{6}=1 \times \frac{6 \times 6 \times 6}{6}=36 m
\end{aligned}
$$

A block of mass \(1 \mathrm{~kg}\) starts from rest at \(\mathrm{x}=0\) and moves along the \(\mathrm{x}\)-axis under the action of a force \(\mathrm{F}=\mathrm{kt}\), where is time and \(k=1 \mathrm{Ns}^{-1}\). The distance the block will travel in 6 seconds is

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